How to calculate the value for C-H bond enthalpy in ethane ?

C2H4 + H2 -----%26gt; C2H6





Delta H = -136 kjmol-1





H-H = 436


C-C = 348





Thank youHow to calculate the value for C-H bond enthalpy in ethane ?
bond enthalpy of reactants (R) is C=C + 4 C-H +H-H= 612+4C-H+436=1048+4C-H





bond enthalpy of prodcuts (P) = C-C+ 6 C-H= 348+6C-H


DELTA H= R-P


or, -136=1048+4C-H-348-6C-H


or. C-H= 418How to calculate the value for C-H bond enthalpy in ethane ?
There isn't enough info. I need the bond enthalpy for C=C.
bond enthalpy of reactants (R) is C=C + 4 C-H +H-H= 612+4C-H+436=1048+4C-H





bond enthalpy of prodcuts (P) = C-C+ 6 C-H= 348+6C-H


DELTA H= R-P


or, -136=1048+4C-H-348-6C-H


or. C-H= 418